Solve 2x2 + 3x – 7 = x2 + 5x + 39 for x.

Ax=-6 + or - the square root of 82
Bx=-6 + or - 2 with the square root of 17
Cx=1 +or - the square root of 33
Dx= 1 + or - the square root of 47

It is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.

Given expression is, 2x²+ 3x – 7 = x² + 5x + 39. Then the equation will be solved as below:-

The solution to the expression is,

2x² + 3x – 7 = x² + 5x + 39

x² - 2x - 46 = 0

( x - 1 )² - 1 - 46 = 0

( x -1 ) ² = 47

( x - 1 ) = ±√47

x = 1 ±√47

Therefore, the solution of the quadratic equation is x = 1 ± √47. The correct option is D.

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Solve 2x2 + 3x – 7 = x2 + 5x + 39 for x. Ax=-6 + or - the square root of 82Bx=-6 + or - 2 with the square root of 17Cx=1 +or - the square root of 33Dx= 1 + or - the square root of 47

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What is a quadratic equation?

Related Questions

Solve 2x2 + 3x – 7 = x2 + 5x + 39 for x.

Ax=-6 + or - the square root of 82
Bx=-6 + or - 2 with the square root of 17
Cx=1 +or - the square root of 33
Dx= 1 + or - the square root of 47