we know that
To find the solution let's factor the equation
\(x^{2} + 4x - 4 = 8\)
Group terms that contain the same variable, and move the constant to the opposite side of the equation
\(x^{2} + 4x = 8+4\)
\(x^{2} + 4x = 12\)
Complete the square. Remember to balance the equation by adding the same constants to each side
\(x^{2} + 4x+4 = 12+4\)
\(x^{2} + 4x+4 = 16\)
Rewrite as perfect squares
\((x+2)^{2} = 16\)
\((x+2)^{2} = 16\\ (x+2)=(+/-)\sqrt{16} \\ x1=-2+\sqrt{16} =-2+4=2\\ x2=-2-\sqrt{16} =-2-4=-6\)
therefore
the answer is the option
A. –6 or x = 2
