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If 2.0 ml of water is added to 8.0 ml of a 0.30 m solution to make a new solution with a total volume of 10.0 ml, what is the concentration of the new solution?

Verified Answer :

taskmasters

To solve this we use the
equation, 

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the
volume of the stock solution, M2 is the concentration of the new solution and
V2 is its volume.

0.30 x 8 = M2 x 10

M2 = 0.24 m of the solution


Hope this answers the question. Have a nice day.

Eduard22sly

The concentration of the new solution is 0.24 M

Data obtained from the question

  • Molarity of stock solution (M₁) = 0.3 M
  • Volume of stock solution (V₁) = 8 mL
  • Volume of water = 2 mL
  • Volume of diluted solution (V₂) = 10 mL
  • Molarity of diluted solution (M₂) =?

How to determine the molarity of diluted solution

M₁V₁ = M₂V₂

0.3 × 8 = M₂ × 10

2.4 = M₂ × 10

Divide both side by 10

M₂ = 2.4 / 10

M₂ = 0.24 M

Learn more about dilution:

https://brainly.com/question/15022582

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