If cos(t)=−9/11 where π<t<3π2, find the values of the following trigonometric function cos(t/2)
cos(t/2) I got .45 is that what you were looking for or do I need to plug it into the equation up top? can you give me notes of something? cos( -9/11/2) = .45
Answer:
\(cos(\frac{t}{2} ) = -\sqrt\frac{1}{11}\)
Step-by-step explanation:
The relationship between cos(t) and cos(\(\frac{t}{2}\)) is:
\(cos(\frac{t}{2} ) = a\sqrt\frac{1+cos(t)}{2}\)
where a is equal to +1 or -1 is same as same sign which cos(t) holds.
Thus, \(cos(\frac{t}{2} ) = -\sqrt\frac{1-\frac{9}{11}}{2}\)
⇒ \(cos(\frac{t}{2} ) = -\sqrt\frac{11-9}{2\times 11}\)
⇒ \(cos(\frac{t}{2} ) = -\sqrt\frac{2}{22}\)
⇒ \(cos(\frac{t}{2} ) = -\sqrt\frac{1}{11}\)