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Verified Answer :

bcalle

Since 121 is a perfect square, 12x12, and 49 is a perfect square, 7x7, and b^4 is a perfect square, b^2xb^2, you have what's called the difference of perfect squares. These factor into the sum and difference of the square roots. So (11b^2+7)(11b^2-7)

Answer:

The factorization of the expression is \(121b^4-49=(11b-7)(11b+7)\)

Step-by-step explanation:

Given : Expression \(121b^4-49\)

To find : What is the factorization of given expression?

Solution :

Expression \(121b^4-49\)

Using algebraic identity,

\(x^2-y^2=(x+y)(x-y)\)

Making the term in square form,

\(121b^4=(11b)^2\)

\(49=7^2\)

So,  \(121b^4-49=(11b)^2-7^2\)

Applying property,

\(121b^4-49=(11b-7)(11b+7)\)

Therefore, The factorization of the expression is \(121b^4-49=(11b-7)(11b+7)\)

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