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How many O2 molecules are present in 0.470 g of oxygen

gas? Can you guys tell me how answer this kind of problem..I appreciate it.

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The number of molecules in 16 grams of oxygen gas is 3.01*10^23, equal to half of Avogadro's number. ... How many molecules of oxygen (o2) are present in 16.0 g of o2…

0.08841875 x \(10^{23}\) molecules are present in 0.470 g of oxygen

gas.

What are moles?

A mole is defined as 6.02214076 × \(10^{23}\)of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

The number of molecules in 16 grams of oxygen gas is 3.01 x \(10^{23}\), equal to half of Avogadro's number.

So, 0.470 g of oxygen gas contains

= (3.01 x \(10^{23}\) x 0.470 g ) ÷ 16

= 0.08841875 x \(10^{23}\)

Hence, 0.08841875 x \(10^{23}\) molecules are present in 0.470 g of oxygen

gas.

Learn more about moles here:

https://brainly.com/question/8455949

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