What is the distance from (−2, 4) to (0, −6)? Round your answer to the nearest hundredth. 9.23 10.20 10.98 11.34
d = \/(0-(-2))² + (-6-4)²
d = \/(0+2)² + (-10)²
d = \/(2² + 100)
d = \/(4+100)
d = \/104
d ~ 10,20
The distance from (-2, 4) to (0, -6) is approximately 10.20 units.
Given two distinct points \(P_{1}\) and \(P_{2}\), the distance between these points is determined by straight line length formula:
\(d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\) (1)
Where \(d\) is the straight line distance between points \(P_{1}\) and \(P_{2}\).
If we know that \(P_{1} = (-2, 4)\) and \(P_{2} = (0, -6)\), then the straight line distance between points \(P_{1}\) and \(P_{2}\):
\(d = \sqrt{[0-(-2)]^{2}+(-6-4)^{2}}\)
\(d \approx 10.198\)
The distance from (-2, 4) to (0, -6) is approximately 10.20.
We kindly invite to see this question on straight line distances: https://brainly.com/question/1156725