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Verified Answer :

mozyztwale

T15=a+(n-1)d
where: "T15" is the 15th term, "a" is the 1st term, "n" is the number of terms and "d" is the common diff.Thus;

53=-3+(15-1)d
53=-3+14d
53+3=14d
56=14d
d=56/14
d=4

Answer:

the common difference = 4

Step-by-step explanation:

First term of an arithmatic sequence is -3

15th term is 53

We need to find the common difference 'd'

Formula for nth term of the sequence is

\(a_n= a_1+(n-1)d\)

where a_1 is the first term and d is the common difference

a1= -3

Lets plug in 15 for n

\(a_n= a_1+(n-1)d\)

\(a_{15}= -3+(15-1)d\), solve for d

\(53= -3+(15-1)d\)

Add 3 on both sides

\(56=(14)d\)

Divide both sides by 14

d=4

So, the common difference = 4

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