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Verified Answer :

SJ2006

Point-slope form, y-y1 = m(x-x1)

(y-(-4)) = -5/6 (x-8)

y+4 = -5x/6+20/3

y = -5x/6+20/3 - 4

y = -5x/6 + 8/3

Answer:

\(y-(-4)=\frac{-5}{4}(x-8)\)

Step-by-step explanation:

Given point = (8,-4)

Slope = \(\frac{-5}{6}\)

General equation of point slope form : \(y-y_1=m(x-x_1)\)

\((x_1,y_1)=(8,-4)\)

\(m=\frac{-5}{6}\)

Substitute the values in general equation :

\(y-(-4)=\frac{-5}{4}(x-8)\)

\(y+4=\frac{-5}{4}(x-8)\)

\(y+4=\frac{-5}{4}x+10\)

\(y=\frac{-5}{4}x+6\)

Hence the equation, in point-slope form, for a line that goes through (8, −4) and has a slope of −5/6  is \(y-(-4)=\frac{-5}{4}(x-8)\)