Answer:
Solution of the given Quadratic equation are +5√2 and -5√2.
Step-by-step explanation:
We are given Quadratic Equation,
\(50-x^2=0\)
To find: Solutions of the given quadratic equation.
Consider,
\(50-x^2=0\)
transpose x² to RHS,
\(50=x^2\)
Now transpose whole RHS to LHS and whole LHS to RHS,
\(x^2=50\)
Now, Apply square root both sides,
\(x=\pm\sqrt{50}\)
\(x=\pm\sqrt{2\times5\times5}\)
\(x=\pm5\sqrt{2}\)
Therefore, Solution of the given Quadratic equation are +5√2 and -5√2.