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apologiabiology

distance between 2 points, (x1,y1) and (x2,y2) is
D=\(\sqrt{(x2-x1)^2+(y2-y1)^2}\)
points (0,0) and (6,3)

D=\(\sqrt{(6-0)^2+(3-0)^2}\)
D=\(\sqrt{(6-0)^2+(3-0)^2}\)
D=\(\sqrt{(6)^2+(3)^2}\)
D=\(\sqrt{36+9}\)
D=\(\sqrt{45}\)
D=3√5

legnth of AB is 3√5

Answer:

Length of ab is:

3√5

Step-by-step explanation:

Distance(D) between 2 points, (x1,y1) and (x2,y2) is  given by

D=\(\sqrt{(x2-x1)^2+(y2-y1)^2}\)

Here we have to find the distance between the points (0,0) and (6,3)

i.e. (x1,y1)=(0,0) and (x2,y2)=(6,3)


D=\(\sqrt{(6-0)^2+(3-0)^2}\)

D=\(\sqrt{(6)^2+(3)^2}\)

D=\(\sqrt{36+9}\)

D=\(\sqrt{45}\)

D=3√5

Hence, Length of ab is:

3√5

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