ok
distance formula
D=\(\sqrt{(x1-x2)^2+(y1-y2)^2}\)
given
distance between (-6,5) and (-3,y) is 5
5=\(\sqrt{(-6-(-3))^2+(5-y)^2}\)
5=\(\sqrt{(-6+3)^2+(5-y)^2}\)
5=\(\sqrt{(-3)^2+(5-y)^2}\)
5=\(\sqrt{9+y^2-10t+25}\)
5=\(\sqrt{y^2-10t+34}\)
square both sides
25= \(y^2-10t+34\)
minus 25 both sides
\(0= y^2-10t+9\)
factor
0=(y-9)(y-1)
set to zero
0=y-9
9=y
0=y-1
1=y
the points are (-3,1) and (-3,9)
