Answer : The mass of the 3.7 mole of \(PbO_2\) is, 885.04 grams
Solution : Given,
Moles of \(PbO_2\) = 3.7 moles
Molar mass of \(PbO_2\) = 239.2 g/mole
Formula used :
\(\text{Mass of }PbO_2=\text{Moles of }PbO_2\times \text{Molar mass of }PbO_2\)
Now put all the given values in this formula, we get the mass of \(PbO_2\)
\(\text{Mass of }PbO_2=(3.7moles)\times (239.2g/mole)=885.04g\)
Therefore, the mass of the 3.7 mole of \(PbO_2\) is, 885.04 grams
