Area of the big rectangle:
\(xy=27000
\\y= \frac{27000}{x}\)
Total length of the fence:
\(\\P=2(x+y)+x
\\P=2x+2y+x
\\P=3x+2y\)
Create function \(P(x)\):
\(\\P(x)=3x+2 \times \frac{27000}{x}
\\P(x)= 3x+ \frac{54000}{x}\)
Find the minimum value for \(x\):
\(\\P'(x)=3- \frac{54000}{x^2}
\\P'(x)=0
\\3- \frac{54000}{x^2}=0
\\3x^2-54000=0
\\x^2=18000
\\x=\sqrt{18000}\)
Find the minimum value for \(y\):
\(\\y= \frac{27000}{x} =\frac{27000}{\sqrt{18000}}\)
Calculate the absolute minimum cost for which the fence for this project can be constructed:
\(\\C=2(x+y) \times \$5 + x \times \$2
\\C=2(\sqrt{18000}+\frac{27000}{\sqrt{18000}})\times \$5+\sqrt{18000} \times \$2
\\C \approx \$3622}\)