we have
\(2x-2y=6\) ------> equation \(1\)
\(4x+4y=28\) ------> equation \(2\)
Multiply by \(2\) the equation \(1\)
\(4x-4y=12\) ------> equation \(3\)
Sum equation \(2\) and equation \(3\)
\(4x+4y=28\\ 4x-4y=12\\ ------\\ 8x=40\\ x=40/8\\ x=5\)
Substitute the value of x in the equation \(2\)
\(4x+4y=28\)
\(4*5+4y=28\\ 4y=28-20\\ 4y=8\\ y=8/4\\y=2\)
therefore
the answer is the option B
\((5,2)\)
