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An unknown substance has a mass of 14.7 g . When the substance absorbs 1.323×102 J of heat, the temperature of the substance is raised from 25.0 ∘C to 45.0 ∘C . What is the most likely identity of the substance?

Aaluminum 0.903
Biron 0.449
Cwater 4.184
Dsilver 0.235
Ecopper 0.385

F. ethanol 2.42

Verified Answer :

metchelle

The correct answer of the given question above would be option B. IRON 0.449. Based on the given details above about an unknown substance that has a mass of 14.7 g and  the substance absorbs 1.323×102 J of heat, the temperature of the substance is raised from 25.0 ∘C to45.0 ∘C, most likely, the substance is IRON. Hope this answers the question.

Answer : The correct option is, (B) iron 0.449

Explanation :

Formula used :

\(Q=m\times c\times \Delta T\\\\Q=m\times c\times (T_2-T_1)\)

where,

Q = heat absorb = \(1.323\times 10^2J\)

m = mass of substance = 14.7 g

c = specific heat of substance = ?

\(\Delta T\) = change in temperature

\(T_1\) = initial temperature = \(25^oC\)

\(T_2\) = final temperature = \(45^oC\)

Now put all the given value in the above formula, we get:

\(1.323\times 10^2J=14.7g\times c\times (45-25)^oC\)

\(c=0.45J/g^oC\)

Form the value of specific heat of substance, we conclude that the metal used in this was iron.

Therefore, the correct option is (B) iron 0.449

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