For this case we must know the unit rate.
To do this, we divide the amount of area covered by the fertilizer, between time.
We have then:
\(r =\frac{\frac{5}{8}}{\frac{1}{4}}\)
Then, rewriting the unit rate we have:
\(r =\frac{4*5}{8*1}\)
\(r =\frac{20}{8}\)
Answer:
the unit rate is:
\(r =\frac{20}{8}\frac{ft^2}{h}\)
