How do you solve 3log_3 4a=3?
3 log₃ 4a=31)a(log_b c)=log_b c^alog₃(4a)³=32) log_a x=n ⇔ a^n=xlog₃ (4a)³=3 ⇔ 3³=(4a)³27=64a³a³=27/64a=∛(27/64)a=3/4Answer: a=3/4