Answer:
Option 4th is correct
\(f(x) = x^2-6x-1\)
Step-by-step explanation:
A quadratic equation is in the form of: \(y=ax^2+bx+c\).....[1]; then the axis of symmetry is given by:
\(x = \frac{-b}{2a}\)
As per the statement:
To find :
The graph of which function has an axis of symmetry at x = 3
From the given options:
Option 4th is the graph of a function which has axis of symmetry at x = 3
Consider a function:
\(f(x) =x^2-6x-1\)
On comparing with [1] we have;
a = 1 and b = -6
then;
\(x = \frac{-(-6)}{2 \cdot 1}\)
⇒\(x = \frac{6}{2} =3\)
Therefore, The graph of which function has an axis of symmetry at x = 3 is, \(f(x) = x^2-6x-1\)
