What are the values of x in the equation 4x2 4x – 3 = 0? x = –1.5, 0.5 x = –0.5, –1.5 x = x =?
4x^2+ 4x – 3 = 0
Using Quadratic Formula:
x = [-4 + sqrt(16+48)]/8
or
x = [-4 - sqrt(16+48)]/8
Solving First equation:
x = [-4 + sqrt(16+48)]/8
= -4+8/8
= 0.5
Solving Second equation:
x = [-4 - sqrt(16+48)]/8
= - 4 - 8 /8
= -12/8
= -1.5
Answer:
The values of x are
\(x=-1.5\ , 0.5\)
Step-by-step explanation:
we have
\(4x^{2}+4x-3=0\)
Group terms that contain the same variable, and move the constant to the opposite side of the equation
\(4x^{2}+4x=3\)
Factor the leading coefficient
\(4(x^{2}+x)=3\)
Complete the square. Remember to balance the equation by adding the same constants to each side.
\(4(x^{2}+x+.25)=3+1\)
\(4(x^{2}+x+.25)=4\)
\((x^{2}+x+.25)=1\)
Rewrite as perfect squares
\((x+0.5)^{2}=1\)
Square root both sides
\(x+0.5=(+/-)1\)
\(x=-0.5(+/-)1\)
\(x=-0.5+1=0.5\)
\(x=-0.5-1=-1.5\)