Write each power as the product of the same factor. Then find the value

7^2

Our Factor is: 7
Our Power is: 2

The power determines the number of times it will multiply by that factor.
So in this case:
7^2 = 7 7 = 49

2^8

Our Factor is: 2
Our Power is: 8

So we need to multiply the factor by itself 8 times. (Think of it as 2 needs to show up 8 times... so if you were to count the number of 2's you'd see there are 8!)

22222222 = (22)(22)(22)(22) = 4444 = (44)(44) = 1616 = (1616) = 256

Or if you want to think of it differently you can do the problem like this:
2^8

22 = 4
42 = 8
82 = 16
162 = 32
322 = 64
642 = 128
1282 = 256

You should see 7, 2's. (It will always be one less than the power)

5^5

Our Factor is: 5
Our Power is: 5

5^5 = 55555 = (55)(55)5 = 25255 = (255)25 = 12525 = 3125

Or you could think of it like this:
55 = 25
255 = 125
1255 = 625
625*5 = 3125

Adetunmbiadekunle Adetunmbiadekunle · Answer 2 · 2021-09-18T02:49:10-04:00

7² = 7 x 7 = 49

2⁸ = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 256

5⁵ = 5 x 5 x 5 x 5 x 5 = 3125

Consider a power of the form \(a^b\) , a represents the base while b is the exponent. To write the power as a product of the same factor, it means a must be multiplied by itself in b places

Applying this rule of powers to the given question, the powers as a product of the same factor are given below.

7² = 7 x 7 = 49

2⁸ = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 256

5⁵ = 5 x 5 x 5 x 5 x 5 = 3125

Learn more here: https://brainly.com/question/8268119