Earl has deposited $798 in a savings account that earns interest at a rate of 3.1% compounded quarterly. What will the account balance be in 21 years?
\(A=P(1+ \frac{r}{n} )^{rt}\)
A=future amount
P=present amount
r=rate in percent
n=number of times per year it is compounded
t=time in years
given
P=798
r=0.031
n=4
t=21
\(A=798(1+ \frac{0.031}{4} )^{(4)(21)}\)
\(A=798(1+ 0.00775 )^{84)}\)
\(A=798(1.00775 )^{84)}\)
A=1526.2956
A=1526.30
about $1526.30