A cyclist is riding his bike up a mountain trail. When he starts up the trail, he is going 8 m/s. As the trail gets steeper, he slows to 3 m/s in 1 minute. What is the cyclist’s acceleration?
Answer:
The cyclist's acceleration is -0.08 m/s².
Explanation:
Given that,
Speed \(v_{i} = 8\ m/s\)
Speed \(v_{f}= 3\ m/s\)
Time = 1 sec
We know that,
The formula of acceleration is defined as:
\(a = \dfrac{v_{f}-v_{i}}{t}\)
Where, a = acceleration
\(v_{f}\)= final speed
\(v_{i}\)= initial speed
We substitute the value into formula
\(a = \dfrac{3-8}{60}\)
\(a= \dfrac{-5}{60}\)
\(a = -0.08 m/s^2\)
Hence, The cyclist's acceleration is -0.08 m/s².