Answer:
You have 17.5 liters of 10% sodium and your friend has 12.5 liters of 22% .
Step-by-step explanation:
We are given that
Total sodium water=30 L
Let you have sodium water=x of 10%
Your friend has sodium water =(30-x) of 22%
We have to find that how many of your liters and your friend liters should you mix to make 30 liters of 15% sodium.
According to question
x of 10%+(30-x) of 22%=30 of 15%
\(\frac{x\times 10}{100}+(30-x)\times \frac{22}{100}=30\times \frac{15}{100}\)
\(\frac{10x}{100}+\frac{660-22x}{100}=\frac{450}{100}\)
\(\frac{10x-22x+660}{100}=\frac{450}{100}\)
\(\frac{-12x+660}{100}=\frac{450}{100}\)
Multiply by 100 on both sides then, we get
\(-12x+660=450\)
\(660-450=12x\)
\(12x=210\)
\(x=\frac{210}{12}=17.5\)
You have 17.5 liters of 10% sodium
Your friend has liters of 22% sodium=30-17.5=12.5 L
