What is the mass in grams of 7.5 x 10^15 atoms of nickel?
Atomic mass Ni = 58.69 a.m.u
58.69 g ----------------- 6.02x10²³ atoms
?? g --------------------- 7.5x10¹⁵ atoms
58.69x (7.5x10¹⁵) / 6.02x10²³
=> 7.31x10⁻⁷ g
Answer:
The mass of \(7,5.10^{15}\) nickel atoms is \(7,34.10^{-7}g\) grams
Explanation:
We want to know how many grams \(7.5.10^{15}\) nickel atoms equals and we know that one mole of any substance equals 6.021023 atoms
To know how many moles correspond \(7.5.10^{15}\) nickel atoms apply a simple rule of three
\(6,02.10^{23} atoms\longrightarrow 1 mol\\7,5.10^{15} atoms\longrightarrow x\\x=\frac{(7,5.10^{15})(1mol) }{6,02.10^23atoms} \\x= 1,25.10^{-8} mol\)
The constant that relates the mass (grams) and the amount of substance (mol) is the molecular mass of the element The nickel molar mass is 58.69g/mol
to know how many grams of nickel correspond \(1,25.10^{-8} mol\) mol we apply a rule of three simple
\(1 mol \longrightarrow 58.69 g\\1,25.10^{-8}\longrightarrow x \\x= \frac{(1,25.10^{-8}mol)(58.69g) }{1mol} \\x=7,34.10^{-7}g\)
The mass of \(7,5.10^{15}\) nickel atoms is \(7,34.10^{-7}g\) grams