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Given the functions a(x) = 3x − 12 and b(x) = x − 9, solve a[b(x)].

Aa[b(x)] = 3x2 – 21
Ba[b(x)] = 3x2 – 39
Ca[b(x)] = 3x – 21
Da[b(x)] = 3x − 39

Verified Answer :

nobillionaireNobley

a(x) = 3x - 12
b(x) = x - 9

a(b(x)) = a(x - 9) = 3(x - 9) - 12 = 3x - 27 - 12 = 3x - 39
a(b(x)) = 3x - 39

Answer:

option (d) is correct.

a[b(x)] = 3x − 39

Step-by-step explanation:

 Given: a(x) = 3x − 12 and b(x) = x − 9

We have to solve for  a[b(x)]

Function composition is defined as  an operation on two functions such that \(P(x)=f(g(x))\) , where we take function f(x) at x = g(x)

Consider  \(a[b(x)]=a(b(x))\)

Substitute the value of b(x) , we have,

\(a(b(x))=a(x-9)\)

Substitute the value of x as x-9 in a(x) , we have,

\(a(x-9)=3(x-9)-12\)

Evaluate , we get,

3(x-9) - 12 = 3x - 27 -12 = 3x - 39

Thus, option (d) is correct.

                 

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