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Alexis has a rectangular piece of red paper that is 4 centimeters wide. it's length is twice it's width. she glues a rectangular piece of blue paper on top of
the red piece measuring 3 centimeters by 7 centimeters how many square centimeters of red paper will be visible on top

Verified Answer :

The area of the red piece of paper is A= 4(24)= 48= 32 in^2.
The area of the blue piece of paper is A= 3*7=21 in^2. You subtract 21 from 32 and the difference is 11. So 11in^2 is visible.

fichoh

The area of the red piece of paper which would be visible is 11 cm²

Recall :

  • Area of rectangle = Length × width

Area of Red rectangular piece of paper :

Width = 4cm

Length = 2 × 4 = 8cm

Area = 4 × 8 = 32 cm²

Area of Blue rectangular piece of paper :

Width = 3cm

Length = 2 × 4 = 7cm

Area = 3 × 7 = 21 cm²

The amount in square inches of red which will be visible can be obtained by subtracting the two area values.

Visible area = 32 cm² - 21 cm² = 11 cm²

Hence, 11 cm² of the red paper will be visible.

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