find the distance from the point (6,10) to the line y=-x to the nearest tenth

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20-10-2016
Mathematics

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find the distance from the point (6,10) to the line y=-x to the nearest tenth

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princegn princegn · Answer 1 · 2016-10-26T15:26:55-04:00

princegn princegn

26-10-2016

points (6,10)
y = -x
x + y = 0

distance = lax1 + by1 + cl/√(a^2 + b^2)
= l1(6) + 1(10) + 0l/√(1^2 + 1^2)
= l6 + 10 + 0l/√(1 + 1)
= l16l/√2
= 16/√2
= 8 .2/√2
= 8 . √2.√2/√2
= 8√2

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