Jon caught four fish that weighed a total of 252 pounds.The kingfish weighed twice as much as the amberjack and the white marlin weighed twice as much as the kingfish.The weight of the tarpon was 5 times the weight of the amberjack.How much did each fish weigh?
1 Amberjack
Kingfish equals 2 Amberjacks
Marlin equals 2 Kingfish or 4 Amberjacks
Tarpon equals 5 AmberJacks
So:
1A plus 2A plus 4A plus 5A equals the 252.
(where A is weight of the AmberJack).
Therefore:
12A equals 252, and A is 21. (252/12 = 21)
Then:
The Amberjack is 21Ibs.
The Kingfish (twice as much as A) is 42Ibs.
The Marlin (four times A) is 84Ibs.
And the Tarpon (five times A) is 105Ibs.
To Check:
21 + 42 + 84 + 105 = 252
Answer:
The kingfish weighed 72 pounds, the amberjack weighed 36 pounds, the white marline weighed 144 pounds and the tarpon weighed 180 pounds.
Step-by-step explanation:
The following fish were caught:
Kingfish, amberjack and white marlin
Let a=pounds of kingfish, b=pounds of amberjack and c=pounds of white marlin and let d=pounds of tarpin
From the information we know that a=2b, c=2a, d=5*b
Let y= the total weighed fish = a+b+c = 252
Therefore we can write y in terms of a:
\(y=252=a+a/2+2*a\)
we can solve a which is:
\(a=252/3.5=72\)
we can solve b as \(b=a/2=72/2=36\) and therefore \(c=2*a=72*2=144\) and \(d=5*b=5*36=180\)
So then y= a+b+c = 72+36+144 = 252 pounds of fish
The kingfish weighed 72 pounds, the amberjack weighed 36 pounds, the white marline weighed 144 pounds and the tarpon weighed 180 pounds.