A race car travels a circular track at an average rate of 135 mi/hr. The radius of the track is 0.450 miles. What is the centripetal acceleration of the car?
Answer : \(a_c=40500\ mi/h^2\).
Explanation :
It is given that,
Velocity of a race car, v = 135 mi/hr
Radius of the track, r = 0.45 miles
We know that the centripetal acceleration is defined as :
\(a_c=\dfrac{v^2}{r}\)
r is the radius of the circle.
\(a_c=\dfrac{(135\ mi/hr)^2}{0.45\ mi}\)
\(a_c=40500\ mi/h^2\)
So, the centripetal acceleration of the car is \(a_c=40500\ mi/h^2\).
Hence, this is the required solution.