For this case we have:
By definition, one of the properties of the power, known as negative integer power, states that:
\(a ^{-b}\)can be written as\(\frac{1}{a ^ b}\)
Thus, \(7 ^{-2}\) can be written as \(\frac{1}{7 ^ 2}\) . So:
\(\frac{1}{7 ^ 2}= \frac{1}{(7 * 7)}=\frac{1}{49}\)
Answer:
Power of negative integer exponent:
\(7^{-2} =\frac{1}{7 ^ 2}= \frac{1}{(7 * 7)}=\frac{1}{49}\)
