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Verified Answer :

minus 1 from both sides
6x^2<-1
divide both sides by 6
x^2<-1/6
take the square root of both sides
x<√(-1/6)
x<i√(1/6)

the solution is i√(1/6)
if you only consider real number, the solution set is empty

Answer:

Solution set of the quadratic equation is, Empty set

Step-by-step explanation:

Given the quadratic equation: \(6x^2+1>0\)  

Subtraction property of equality states that you subtract the same number to both sides of an equation.

Subtract both sides by 1 we get;

\(6x^2+1-1>0-1\)

Simplify:

\(6x^2>-1\)

Division property of equality states that you divide the same number to both sides of an equation.

Divide both sides by 6 we get;

\(\frac{6x^2}{6} >\frac{-1}{6}\)

Simplify:

\(x^2>\frac{-1}{6}\)

For any x in real number there does not exist any number x which satisfy

\(x^2>\frac{-1}{6}\) , therefore, there is no solution for this set of the quadratic inequality or in other word we can say that set of the solution is Empty set.