What is the solution set of the quadratic inequality 6x2+1<0
minus 1 from both sides
6x^2<-1
divide both sides by 6
x^2<-1/6
take the square root of both sides
x<√(-1/6)
x<i√(1/6)
the solution is i√(1/6)
if you only consider real number, the solution set is empty
Answer:
Solution set of the quadratic equation is, Empty set
Step-by-step explanation:
Given the quadratic equation: \(6x^2+1>0\)
Subtraction property of equality states that you subtract the same number to both sides of an equation.
Subtract both sides by 1 we get;
\(6x^2+1-1>0-1\)
Simplify:
\(6x^2>-1\)
Division property of equality states that you divide the same number to both sides of an equation.
Divide both sides by 6 we get;
\(\frac{6x^2}{6} >\frac{-1}{6}\)
Simplify:
\(x^2>\frac{-1}{6}\)
For any x in real number there does not exist any number x which satisfy
\(x^2>\frac{-1}{6}\) , therefore, there is no solution for this set of the quadratic inequality or in other word we can say that set of the solution is Empty set.