Answer:
\(sin(30\°)*sin(60\°)=cos(60\°)*cos(30\°)\)
Step-by-step explanation:
we know that
\(sin(\alpha)=cos(\beta)\)
when
\(\alpha+\beta=90\°\) -------> complementary angles
so
\(sin(30\°)=cos(60\°)\)
\(sin(60\°)=cos(30\°)\)
Because
\(30\°+60\°=90\°\) -------> complementary angles
In this problem the product of
\(sin(30\°)*sin(60\°)\)
is equal to
\(cos(60\°)*cos(30\°)\)
therefore
\(sin(30\°)*sin(60\°)=cos(60\°)*cos(30\°)\)
