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let f (x)=x^2 + 6 and g (x) =x+8/x find (g o f) (-7)

A384 /7
B-57/7
C295 /49
D63/55

its not C i got that one wrong


any help would be appreciated thank you

Verified Answer :

i hope this helps you

View image Anonymous

The value of g(f(-7)) is 63/55 and this can be determined by using the given data and the function properties.

Given :

  • \(\rm f(x) = x^2+6\)
  • \(\rm g(x) = \dfrac{x+8}{x}\)

First, determine the value of f(-7).

\(\rm f(-7) = (-7)^2+6\)

f(-7) = 49 + 6

f(-7) = 55

Now, the expression of g(f(x)) is given by:

\(\rm g(f(x)) = \dfrac{x^2+6+8}{x^2+6}\)

\(\rm g(f(x)) = \dfrac{x^2+14}{x^2+6}\)

Now, substitute the value of (x = -7) in the above expression.

\(\rm g(f(x)) = \dfrac{(-7)^2+14}{(-7)^2+6}\)

\(\rm g(f(x)) = \dfrac{49+14}{49+6}\)

\(\rm g(f(x)) = \dfrac{63}{55}\)

The value of g(f(-7)) is 63/55 and this can be determined by using the given data and the function properties. Therefore, the correct option is d).

For more information, refer to the link given below:

https://brainly.com/question/21114745