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Two blocks of mass 3.50 kg and 8.00 kg are connected by a Mass less string that passes over a frictionless pulley (Fig.P5.68). The inclines are frictionless. Find (

Athe magnitude of the acceleration of each block and (
Bthe tension in the string.

Verified Answer :

The mass on the left has a downslope weight of 
W1 = 3.5kg 9.8m/s² sin35º = 19.7 N 
The mass on the right has a downslope weight of 
W2 = 8kg 9.8m/s² sin35º = 45.0 N 
The net is 25.3 N pulling downslope to the right. 

(a) Therefore we need 25.3 N of friction force. 
Ff = 25.3 N = µ(m1 + m2)gcosΘ = µ 11.5kg 9.8m/s² cos35º 
25.3N = µ 92.3 N 
µ = 0.274 

(b) total mass is 11.5 kg, and the net force is 25.3 N, so 
acceleration a = F / m = 25.3N / 11.5kg = 2.2 m/s² 

tension T = 8kg (9.8sin35 - 2.2)m/s² = 27 N 

Check: T = 3.5kg (9.8sin35 + 2.2)m/s² = 27 N √ 

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