how many moles of HF are needed to react with 0.300 mol of Na2SiO3?
Na2SiO3(s) + 8 HF(aq) ___> H2SiF6(aq) + 2 NaF(aq) + 3 H2O(l)
as per the equation , one mole of Na2SiO3 requires 8 moles of HF.
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The moles of HF are needed to react with 0.300 mol of Na₂SiO₃ is 2.4 moles.
Stoichiometry of any reaction tells about the amount of species present before and after the completion of chemical reaction.
Given chemical reaction will be represent as:
Na₂SiO₃(s) + 8HF(aq) → H₂SiF₆(aq) + 2NaF(aq) + 3H₂O(l)
From the stoichiometry of the reaction it is clear that:
1 mole of Na₂SiO₃ = react with 8 moles of HF
0.30 mole of Na₂SiO₃ = react with 8×0.30=2.4 moles of HF
Hence, required moles of HF is 2.4 moles.
To know more about stoichiometry, visit the below link:
https://brainly.com/question/16060199