The slope of the line is represented by the equation 2x+3y= -12 and 2x+3y= -12 is \(\frac{-2}{3}\).
Given that,
2x + 3y = -12
Now here we isolated the variable y
2x + 3y = -12
Now subtract 2x from both sides
3y = -2x - 12
Now divide by 3 in both the sides.
\(y = \frac{-2}{3}x - 4\)
Now
The slope m should be \(\frac{-2}{3}\).
Therefore we can conclude that the slope of the line is represented by the equation 2x+3y= -12 and 2x+3y= -12 is \(\frac{-2}{3}\).
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