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ismahmuslimah
ismahmuslimah ismahmuslimah
  • 26-11-2014
  • Mathematics
Answered

Himpunan penyelesaian dari pertidaksamaan | 2x + 1| ≤ 3 adalah.....

A{ -1 ≤ x ≤3 }
B{ -2 ≤ x ≤ 2}
C{ -2 ≤ x ≤ 1 }
D{ -1 ≤ x ≤ 1 }
E{ 0 ≤ x ≤ 1 }

Tolong caranya...

Verified Answer :

konrad509
konrad509 konrad509
  • 26-11-2014

\(| 2x + 1| \leq3 \\ 2x+1\leq3\wedge2x+1\geq-3\\ 2x\leq2 \wedge 2x\geq-4\\ x\leq1 \wedge x\geq-2\\ -2\leq x \leq1 \Rightarrow C\)

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