we know that
If two lines are parallel , then their slopes are the same
we will proceed to calculate the slope of each line to determine the solution.
The formula to calculate the slope m between two points of the line is equal to
\(m=\frac{(y2-y1)}{(x2-x1)}\)
case N 1) line AB
Let
\(A(-4,3)\\B(4,3)\)
substitute the values
\(m=\frac{(3-3)}{(4+4)}\)
\(m=\frac{(0)}{(8)}\)
\(m=0\)
\(0
eq 3\)
therefore
The line AB is not the solution
vase N 2) line FG
Let
\(F(-3,-1)\\G(3,-3)\)
substitute the values
\(m=\frac{(-3+1)}{(3+3)}\)
\(m=\frac{(-2)}{(6)}\)
\(m=-1/3\)
\(-1/3
eq 3\)
therefore
The line EG is not the solution
case N 3) line CD
Let
\(C(-3,0)\\D(3,2)\)
substitute the values
\(m=\frac{(2-0)}{(3+3)}\)
\(m=\frac{(2)}{(6)}\)
\(m=1/3\)
\(1/3
eq 3\)
therefore
The line CD is not the solution
case N 4) line HJ
Let
\(H(-1,-4)\\J(1,2)\)
substitute the values
\(m=\frac{(2+4)}{(1+1)}\)
\(m=\frac{(6)}{(2)}\)
\(m=3\)
\(3=3\)
therefore
The line HJ is the solution
therefore
the answer is the option
line HJ
