mickaelasalazar
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The magnitude of the electrical force acting between a +2.4 × 10–8 C charge and a +1.8 × 10–6 C charge that are separated by 0.008 m is N, rounded to the tenths place.

Verified Answer :

Edufirst

Use Coulomb law: F = k q1q2 / (r^2), where k = 9.00 10^9 N.m^2/C^2

F = 9.00 10^9 N.m^2/C^2 2.410^-8 C 1.810^-6 C / [0.008m]^2 = 38.88 10^ -5 N

F = 39 10 -5N


onyebuchinnaji

The magnitude of the electrical force acting between the two charges is 6.1 N.

Magnitude of the electric force

The magnitude of the electric force is calculated as;

F = kq₁q₂/r²

where;

  • q₁ and q₂ are the two charges
  • r is the distance between the charges
  • k is coulomb's constant

F = (9 x 10⁹ x 2.4 x 10⁻⁸ x 1.8 x 10⁻⁶)/(0.008)²

F = 6.1 N

Learn more about electric force here: https://brainly.com/question/20880591

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