how much thermal energy is required to heat 15.2g of a metal (specific heat = 0.397 J/g * degrees celsius) from 21.0 degrees celsius to 40.3 degrees celsuis?

Verified Answer :

depends on the conducter

Answer: The amount of heat required is 116.5 Joules

Explanation:

To calculate the amount of heat absorbed, we use the equation:

\(q=m\times C\times \Delta T\)

where,

q = amount of heat absorbed = ?

m = mass of metal = 15.2 g

C = specific heat capacity of metal = \(0.397J/g^oC\)

\(\Delta T\) = change in temperature = \((T_2-T_1)=(40.3-21.0)^oC=19.3^oC\)

Putting all the values in above equation, we get:

\(q=15.2g\times 0.397J/g^oC\times 19.3^oC\\\\q=116.5J\)

Hence, the amount of heat required is 116.5 Joules