Elijah throws a tennis ball vertically upward. The ball returns to the point of release after 3.5 s. What is the speed of the ball as it is released?
t(return)=3.5 s
h = vt - (1/2)gt^2
to the point of release or return h=0
vt - (1/2)gt^2=0
t(v - gt/2)=0 ==>
t(release)=0 or v - (1/2)gt(return)=0 ==>
v = (1/2)gt(return)
v=9.81*3.5/2
v=17.17 m/s
Hope i helped! :)
The speed of the ball as it is released is 17.15 m/s.
The acceleration should be 9.8
The time taken should be 3.5 seconds
Now the speed is
\(= 9.8 \times 3.5\)
= 17.15 m/s
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