Verified Answer :

 2 moles of N2O5 = 4 moles of NO2 

2.4 mol N2O5/1 X 4 mol NO2/2 mol N2O5 (this way you can cross out the N2O5 mol and just be left with NO2 mol) 

2.4 X 4 = 9.6 

9.6/2 = 4.8 

4.8 mol NO2 are formed

Answer: 4 moles of \(NO_2\) will be formed when \(N_2O_5\) completely reacts.

Explanation: We are given a chemical reaction for the decomposition of \(N_2O_5\).

Balanced Chemical equation follows when complete reaction occurs:

\(2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)\)

By Stoichiometry,

2 moles of \(N_2O_5\) produces 4 moles of \(NO_2\) and 1 mole of \(O_2\).

Therefore, 4 moles of \(NO_2\) will be produced when \(N_2O_5\) reacts completely.

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