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Verified Answer :

Moly42

\(Ba^{2+} + S^{2-}\)
\(BaS\)

Answer: The chemical formula for the compound formed will be \(BaS\)

Explanation:

Barium is the 56th element of the periodic table having electronic configuration of \([Xe]6s^2\)

This element looses 2 electrons and thus shows an oxidation state of +2 units.

Sulfur is the 16th element of the periodic table having electronic configuration of \([Ne]3s^23p^4\)

This element requires 2 electrons and thus shows an oxidation state of -2 units.

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

Thus, the chemical formula for the compound formed will be \(BaS\)

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