What is the 14th term for the geometric sequence 8, -16, 32, -64,
here we go
an=a1(r^(n-1))
a1=first term
r=common ratio
n=which term
common ratio is -2 (8 times -2=-16, -16-2=32)
first term is 8
n is 14
a14=8(-2)^(14-1)
a14=8(2)^13
a14=8(-8192)
a14=-65536