z=(x-mu)/sd
z=(32-33)/.7
z= -1.43
look this up in z score table and you get .4236. This is the area above a weigth of 32 and below the mean weight of 33. So the proportion that are underweight = .5 - .4236 = .0764
z=(x-mu)/sd
1.645=(x-33)/.7
Solving for x gives 34.15
(we get 1.65 by finding the area above the mean of .4500 in the table. Bottom half (.5) + .4500 = .95)
Therefore, the answer would be letter A. 0.0764.
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