Verified Answer :

Hagrid

The general form of the equation \(5x^{2} -20x = 15\) is \(x^{2} -4x -3 =0\). The general form of an equation is \(A x^{2} + Bx +C=0\)

Dividing the whole equation by 5 and transferring 3 to the left side yields the answer \(x^{2} -4x-3 = 0\)

Answer:

Option B is correct

\(x^2-4x-3 = 0\)

Step-by-step explanation:

The general form of the equation is given by:

\(Ax^2+Bx+C = 0\)

Given the equation:

\(5x^2-20x = 15\)

⇒\(5(x^2-4x) = 15\)

Divide both sides by 5 we have;

\(x^2-4x =3\)

Subtract 3 from both sides we have;

\(x^2-4x-3 = 0\)

Therefore, the general form of the equation is, \(x^2-4x-3 = 0\)