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yountenbryff
yountenbryff yountenbryff
  • 18-10-2016
  • Mathematics
Answered

What is the sum of a 58–term arithmetic sequence where the first term is 6 and the last term is 405? please helpp.

Verified Answer :

apologiabiology
apologiabiology apologiabiology
  • 18-10-2016

the sum of an arythmetic sequence for first term, a1 and last term, an and up to the term, n is
\(s_n= \frac{n(a1+an)}{2}\)
n=58
a1=6
a58=405

\(s_{58}= \frac{58(6+405)}{2}\)
\(s_{58}= \frac{58(411)}{2}\)
\(s_{58}= \frac{23838}{2}\)
\(s_{58}= 11919\)


sum is 11,919


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