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Verified Answer :

lovinglol4

Zr has atomic number 40 , so it need to lose 4 electrons to gain noble gas configuration of the noble gas Kr

sebassandin

Answer:

4 electrons are lost.

Explanation:

Hello,

Zirconium's electron configuration is:

\(Zr^{40}=1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^2\)

This allows us to infer that when all the electrons present at both the \(5s^2\) and the \(4d^2\) orbitals, 4 electrons are lost (two from \(5s^2\) and two from \(4d^2\)), allowing the \(Zr^{4+}\) species to exist.

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