Estimate the heat of neutralization of H3PO4 in kJ/mol given these data: Heat transferred = 2.5 x 102 J Moles of H3PO4 = 1.4 x 10−3 mol Moles of NaOH = 5.0 x 10−3 mol

Question

17-10-2016
Chemistry

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Estimate the heat of neutralization of H3PO4 in kJ/mol given these data: Heat transferred = 2.5 x 102 J Moles of H3PO4 = 1.4 x 10−3 mol Moles of NaOH = 5.0 x 10−3 mol

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Anonymous Anonymous · Answer 1 · 2016-10-18T06:11:42-04:00

Below are the steps to get the answers:

1.) write out the balance equation
3NaOh+H3PO4->Na3PO4+3H2O

2.) You are given everything needed to calculate
q=heat transfer=2.210^2, H3PO4 moles= 1.510^-3, NaOH moles=5.010^-3

3.) equation is deltaHneutraliztion=q/Moles of limiting reagent
H3PO4 is limiting reagent because lowest moles, and is used up first

4.) Now plug in variables
DeltaH=2.210^2(1.5*10^3)= 146.67kj/mole
Notice we had to convert J to kj,